Answer:
[tex]h_{pole}=30ft[/tex]Explanation: We have to find the height of the pole, which is just an opposite side of a triangle, we would have to resort to the pythagorean theorem and one of the trigonometric ratios, this is done as follows:
[tex]\begin{gathered} \text{ Base is determined through pythagorean theorem:} \\ \Rightarrow a^2+b^2=c^2\rightarrow a=b \\ \therefore\rightarrow \\ 2a^2=27^2\Rightarrow a=b=\frac{27}{\sqrt[]{2}}=\frac{27\sqrt[]{2}}{2} \\ \end{gathered}[/tex]Height of the pole:
[tex]\begin{gathered} \tan (57^{\circ})=\frac{Opposite\text{ }}{\text{Adjacent}}=\frac{h}{b}=\frac{h}{(\frac{27\sqrt[]{2}}{2})} \\ \tan (57^{\circ})=\frac{2h}{27\sqrt[]{2}}\rightarrow h=\frac{27\sqrt[]{2}}{2}\tan (57^{\circ})=\frac{27\sqrt[]{2}}{2}\times(1.54)=29.40\cong30 \\ \therefore\rightarrow \\ h_{pole}=30ft \end{gathered}[/tex]