Given that s varies jointly with t and the cube of r.
We have to tell that if t is halved and r is doubled, what happens to s.
From the question, we can say that,.
[tex]s\propto t\times(r)^3\Rightarrow s=ktr^3[/tex]Given that t is halved and r is doubled. Then,
[tex]\begin{gathered} s=k(\frac{t}{2})(2r)^3 \\ s=k(\frac{t}{2})(8r^3) \\ s=4\text{ktr}^3 \end{gathered}[/tex]Thus, s becomes 4 times.