Respuesta :

ANSWER

[tex]\begin{gathered} 1)5.695 \\ Nth\text{ term }\frac{1}{2}\times(\frac{3}{2})^{n-1} \end{gathered}[/tex]

EXPLANATION

1.

Given;

[tex]\frac{1}{2},\frac{3}{4},\frac{9}{8}[/tex]

Recall;

[tex]T_n=a\times r^{n-1}[/tex]

Coommon ratio

[tex]\begin{gathered} r=\frac{T_2}{T_1} \\ =\frac{3}{4}\div\frac{1}{2} \\ =\frac{3}{4}\times\frac{2}{1} \\ =\frac{2}{3} \end{gathered}[/tex]

Hence;

[tex]\begin{gathered} a=\frac{1}{2},r=\frac{3}{2} \\ \end{gathered}[/tex]

Substituting the values;

[tex]\begin{gathered} T_{n}=ar^{n-1} \\ =\frac{1}{2}\times(\frac{3}{2})^{7-1} \\ =0.5\times1.5^6 \\ =11.39\times0.5 \\ =5.695 \end{gathered}[/tex]

Nth term;

[tex]\begin{gathered} T_n=\frac{1}{2}\times(\frac{3}{2})^{n-1} \\ \end{gathered}[/tex]

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