Question

g(t)=(t+1)^2-20.25what is the vertex of the parabola? (___,___)

Answer 1

$\begin{gathered} (t+1)^2-20.25=0 \\ (t+1)^2-20.25=0 \\ t^2+t+1-2.25=0 \\ t^2+t-19.25=0 \end{gathered}$

Solving for t,

$\frac{-1\pm\sqrt[]{1+4\times19.25}}{2}=\frac{-1\pm8.8}{2}=3.5;-5.5$