Given,
[tex]|4x+3|=|2x-5|[/tex]Removing the absolute value we have four condition,
[tex]-(4x+3)=-(2x-5)\ldots\ldots\text{.}(1)[/tex][tex]\Rightarrow-2x=8\Rightarrow x=-4[/tex][tex]-(4x+3)=(2x-5)\Rightarrow x=\frac{1}{3}\ldots\text{.}(2)[/tex][tex](4x+3)=-(2x-5)\Rightarrow x=\frac{1}{3}\ldots\ldots\text{.}\mathrm{}(3)[/tex][tex]4x+3=2x-5\Rightarrow x=-4\ldots\ldots(4)[/tex]Thus x can have two values x=-4,1/3.
