Respuesta :

Explanation

Given

[tex]\frac{40x^{-2}y^{-3}z^0}{5x²y^{-4}z^{-2}}[/tex]

Therefore,

[tex]\begin{gathered} \frac{40x^{-2}y^{-3}z^0}{5x^2y^{-4}z^{-2}} \\ =\frac{5\cdot \:8x^{-2}y^{-3}}{5x^2y^{-4}z^{-2}} \\ =8x^{-2-2}y^{-3+4}z^{-2} \\ =8x^{-4}y^1z^{-2} \\ =\frac{8y}{x^4z^{-2}} \\ =\frac{8yz^2}{x^4} \end{gathered}[/tex]

Answer:

[tex]\frac{8yz^2}{x^4}[/tex]

ACCESS MORE
EDU ACCESS