write an equation in slope intercept form form for the line that passes through (-3,5) and is parallel to the graph of the line y=1/3x+4

Respuesta :

If the line is parallel to

[tex]y=\frac{1}{3}x+4[/tex]

Then it has a slope of 1/3.

Using this slope, point (-3, 5) and the slope-point form,

[tex]\begin{gathered} y-5=\frac{1}{3}(x+3) \\ \rightarrow y-5=\frac{1}{3}x+1 \end{gathered}[/tex]

Clearing y to get the slope-intercept form,

[tex]\begin{gathered} y-5=\frac{1}{3}x+1 \\ \rightarrow y=\frac{1}{3}x+6 \end{gathered}[/tex]

We get that the equation of the line in slope-intercept form is:

[tex]y=\frac{1}{3}x+6[/tex]

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