Question

The length of a rectangular playground is 4 feet more than its width. The area of the playground is 140 square feet. Set up and solve an equation to find the length and width of the playground.

Answer 1

$(4+x)(x)=140$

then

$4x+x^2=140$$x^2+4x-140=0$$x=\frac{-4+\sqrt[]{4^2-4(1)(-140)}}{2}=\frac{-4+\sqrt[]{16+560}}{2}=\frac{-4+24}{2}=10$

or

$x=\frac{-4-24}{2}=\frac{-28}{2}=-14$

Since x is a width, then x cannot be a negative number then the final answer will be x=10 then the width is 10 and the length is 14