Question

I was able to find part A. But need help with part B & C

Answer 1

To find the magnitude, we have to use the following formula

$|d|=\sqrt[]{x^2+y^2}$

Where x = 1 and y = 3, let's use these values to find the magnitude.

$\begin{gathered} |d|=\sqrt[]{1^2+3^2}=\sqrt[]{1+9}=\sqrt[]{10} \\ |d|\approx3.2 \end{gathered}$

The magnitude of the resultant vector is 3.2 meters, approximately.

To find the direction, we have to use the following formula

$\begin{gathered} \theta=\tan ^{-1}(\frac{y}{x})=\tan ^{-1}(\frac{3}{1}) \\ \theta\approx71.6 \end{gathered}$

The direction of the resultant vector is 71.6°.