Given a quadratic equation with the following form
[tex]y=ax^2+bx+c[/tex]
The quadratic equation is
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]
The equation given is
[tex]y=x^2-5x-14[/tex]
Our coefficients are
[tex]\begin{gathered} a=1 \\ b=-5 \\ c=-14 \end{gathered}[/tex]
Rewritting the quadratic formula using those values, we have:
[tex]x=\frac{-(-5)\pm\sqrt[]{(-5)^2-4(1)(-14)}}{2(1)}[/tex]
