Hi, can you help me to solve and explain to me how to find the results please!

0. Irrational
,1. Irrational
,2. Rational
,3. Irrational
1) Considering that Rational Numbers are the ones that can be written as ratios like:
[tex]\begin{gathered} \frac{a}{b} \\ 1,\frac{3}{2},5,\text{ }\sqrt[]{4} \end{gathered}[/tex]2) Then we can examine each row and each expression as well. So we can begin with:
[tex]3\sqrt[]{9}\cdot\sqrt[]{2}=3\cdot3\cdot\sqrt[]{2}=9\sqrt[]{2}=12.72792\ldots[/tex]Since the square root of 2 yields an irrational number, 9 times that yields an irrational one as well.
Irrational
[tex]\frac{\sqrt[]{9}}{\pi}=\frac{3}{\pi}=0.9452\ldots[/tex]Note that in the second row we have an irrational number as well, a decimal and not a repeating number.
Irrational
[tex]\frac{\pi\sqrt[]{24}}{\sqrt[]{6\pi^2}}=\frac{\pi\cdot2\sqrt[]{2}\cdot\sqrt[]{3}}{\pi\sqrt[]{2}\cdot\sqrt[]{3}}=2[/tex]Since 2 is a rational number the same as 2/1. This is a Rational one.
And Finally:
[tex]-\sqrt[]{3}+2=0.2674[/tex]Notice that the square root of 3 is already irrational so the sum of that with 2 yields another irrational number.
Irrational
3) Hence, the answer is:
0. Irrational
,1. Irrational
,2. Rational
,3. Irrational