Hello there. To solve this question, we'll have to remember some properties about growth or decay functions and how to rewrite expressions.
Given the expression no. 30:
[tex]y=a(0.25)^{\frac{t}{9}}[/tex]
We can rewrite:
[tex]0.25=1-0.75[/tex]
Therefore we have:
[tex]y=a(1-0.75)^{\frac{t}{9}}[/tex]
In this case, we get r = 0.75, that means a decay rate, because the values will get smaller and smaller as t increases.
The end behavior of this function is getting close to zero when t is sufficiently large.
