Question

Consider the function:h(x) = – 2x^3 + 2x^2 + 4x + 3Find the value of h(-1).

Answer 1

Function:

$h(x)=-2x^3+2x^2+4x+3$

Finding the value of h(-1):

$\begin{gathered} h(-1)=-2(-1)^3+2(-1)^2+4(-1)+3 \\ h(-1)=-2(-1)^{}+2(1)^{}+4(-1)+3 \\ h(-1)=2^{}+2^{}-4+3 \\ h(-1)=4^{}-4+3 \\ h(-1)=3 \end{gathered}$

Answer: h(-1) = 3