ANSWER
The pressure of the gas is 743.4 Kpa
EXPLANATION
Given that;
The volume of the gas is 12L
The number of moles of the gas 3.70 moles
The temperature of the gas is 290K
Follow the steps below to find to the pressure of the gas
The ideal gas equation is given below as
[tex]\text{ PV = nRT}[/tex][tex]\begin{gathered} \text{ R = 8.314 L.Kpa. mol}^{-1}K^{-1} \\ \text{ P }\times\text{ 12 = 3.70}\times\text{ 290}\times\text{ 8.314} \\ \text{ 12P = 8290.922} \\ \text{ Divide both sides by 12} \\ \text{ P = }\frac{\text{ 8290.922}}{\text{ 12}} \\ \text{ P = 743.4 Kpa} \end{gathered}[/tex]Therefore, the pressure of the gas is 743.4 Kpa
