Respuesta :

a) Not a factor

b) Not a factor

1) To check whether those given polynomials are factors of f(x), we need to remind of the definition of the factor theorem:

2) So, let's begin with p+2

[tex]\begin{gathered} p+2=0 \\ p=-2 \\ f(2)=(2)^4+6\cdot(2)^3+11(2)^2+29(2)-13 \\ f(2)=16+48+44+58-13 \\ f(2)=153 \end{gathered}[/tex]

Since f(2) is not equal to zero then (p+2) is not a factor

b)p+5

Similarly, we can write out the following:

[tex]\begin{gathered} p+5=0\rightarrow p=-5 \\ f(-5)=(-5)^4+6(-5)^3+11(-5)^2+29(-5)-13 \\ f(-5)=625-750+275+29\left(-5\right)-13 \\ f(-5)=625-750+275-145-13 \\ f(-5)=-8 \end{gathered}[/tex]

As we can see, p+5 is also not a factor of f(x), in other words, -5 is not a root as well as 2 of this polynomial.

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