Write the perimeter of the triangle as a simplified expression.a3y + 56y-y - 4

10y+1
Explanation
The perimeter of a triangle is simply the sum of its three sides.
so
Step 1
let
[tex]\begin{gathered} \text{side}_1=3y+5 \\ \text{side}_2=y-4 \\ \text{side}_3=6y \end{gathered}[/tex]hence, the perimeter would be
[tex]\begin{gathered} \text{Perimeter}=side_1+side_2+side_3 \\ \text{replace} \\ \text{Perimeter}=3y+5+y-4+6y \\ \text{add like terms} \\ \text{Perimeter}=(3y+y+6y)+(5-4) \\ \text{Perimeter}=10y+1 \end{gathered}[/tex]therefore, the perimeter is
10y+1
I hope this helps you