Question

what is the value of f(-3) when f(x)=x^2+4x+5

Answer 1

$f(-3)=2$

Explanation

$f(x)=x^2+4x+5$

Step 1

replace

when x=-3

then,

$\begin{gathered} f(x)=x^2+4x+5 \\ f(-3)=(-3)^2+4(-3)+5 \\ f(-3)=9-12+5 \\ f(-3)=2 \end{gathered}$

I hope this helps you