Answer:
[tex]\textsf{A.} \quad x < -4[/tex]
B. To graph the solution to the inequality on number line, place an open circle at -4 and shade to the left of the circle.
C. x = -5, x = -6
Step-by-step explanation:
Given inequality:
[tex]-6(x-3) > 42[/tex]
To solve the inequality, divide both sides by -6 (remembering to reverse the inequality symbol as we are dividing by a negative number):
[tex]\implies \dfrac{-6(x-3)}{-6} > \dfrac{42}{-6}[/tex]
[tex]\implies x-3 < -7[/tex]
Add 3 to both sides:
[tex]\implies x-3+3 < -7+3[/tex]
[tex]\implies x < -4[/tex]
When graphing an inequality on a number line:
To graph the solution to the inequality on number line, place an open circle at -4 and shade to the left of the circle.
(See the attachment for the solution graphed on a number line).
Two values that would make the inequality true, are any values of x that are less than -4. For example:
We know the two values are solutions to the inequality as they are both included in the shaded part of the solution represented on the number line (from part B).