Question

suppose that the function V = 40x to the 2nd -500× + 5000 describes the value of a car from 1960 to 2012. What year did the car have the least value? (x = 0 is 1960)

Answer 1

We have the next function

$V=40x^2-500x+5000$

In 1960, x=0

$V=5000$

In 1965, x=5

$V=3500$

In 1966, x=6

$V=3440$

In 1967, x=7

$V=3460$

In 1968, x=8

$V=3560$

As we can see the year with the least value is 1966