Question

The length of a rectangle is twice its width. If the perimeter of the rectangle is 60 inches, find its length and width.

Answer 1

Answer: length 20

width 10

Step-by-step explanation:

L = 2W

W+W+L+L=60

2W+2W+2W=60

6W=60

•1/6 to both sides

W=10

L=20

Answer 2

Answer:

Length = 20 in

Width = 10 in

Step-by-step explanation:

Given information:

• The length of a rectangle is twice its width.
• The perimeter of the rectangle is 60 inches.

Define the variables:

• x = width
• 2x = length

Perimeter of a rectangle

$P = 2(w + l)$

where:

• w = width
• l = length

Substitute the given values into the formula and solve for x:

$\begin{aligned}\textsf{Perimeter of rectangle}&=\sf 2(width + length)\\\implies 60&=2(x+2x)\\60&=2(3x)\\60&=6x\\x&=10\end{aligned}$

Substitute the found value of x into the expressions for width and length.

Solution

• Length = 20 in
• Width = 10 in