Question

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A line passes through the point (-4, -5) and has a slope of 4.

Write an equation in slope intercept form for this line.

Answer 1

Answer:

See below

Step-by-step explanation:

I'll start with point (-4, -5) slope form and convert

Point slope form

( y - - 5)  = 4 ( x - - 4)     simplify

y + 5 = 4x + 16     subtract 5 from both sides

y = 4x + 11        Done .

Answer 2

Answer:

$y=4x+11$

Step-by-step explanation:

$\boxed{\begin{minipage}{6.3 cm}\underline{Slope-intercept form of a linear equation}\\\\ y=mx+b \\\\where:\\ \phantom{ww} \bullet m is the slope. \\ \phantom{ww} \bullet b is the y -intercept.\\\end{minipage}}$

Given values:

• Slope = 4
• Point on the line = (-4, -5)

Substitute the given slope and point into the slope-intercept formula and solve for b:

$\implies -5=4(-4)+b$

$\implies -5=-16+b$

$\implies -5+16=-16+b+16$

$\implies 11=b$

$\implies b=11$

Substitute the found y-intercept (value of b) and the given slope into the formula to create an equation in slope-intercept form of the line:

$\large\boxed{y=4x+11}$