The perimeter and area of the given polygon is 24 inches and 20 square inches respectively.
According to the question,
We have a figure with each side being 2 inches.
We know that the perimeter of a figure is sum of all of its sides.
Now, the total number of sides we have are 12.
So, we have:
Perimeter of the polygon = sum of all 12 sides
Perimeter of the polygon = 12*2 (because each side is equal)
Perimeter of the polygon = 24 inches
Now, we know that in a square all four sides are equal. If we observe the given polynomial then we notice that there are 5 squares in it. Out of these 5 squares, 4 are formed with real lines and 1 imaginary line and there is 1 imaginary square in the center with its sides as 2 inches.
We know that the area of square is (side*side).
Area of 5 squares = 5*(side*side)
Area of 5 squares = 5*(2*2) square inches
Area of 5 squares = 5*4 square inches
Area of 5 squares = 20 square inches
Hence, the correct option is A (the first one with 24 inches of perimeter and 20 square inches of square).
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