Answer:
[tex]3\, x + (-1)\, y = 1[/tex].
Step-by-step explanation:
Both the slope of this line and the coordinates of a point on this line are given. Therefore, start by finding the point-slope equation of this line: if the slope of a line in a plane is [tex]m[/tex], and this line goes through a point at [tex](x_{0},\, y_{0})[/tex], the point-slope equation of this line will be [tex](y - y_{0}) = m\, (x - x_{0})[/tex].
The slope of the line in this question is [tex]m = 3[/tex]. It is given that this line goes through the point [tex](2,\, 5)[/tex], where [tex]x_{0} = 2[/tex] and [tex]y_{0} = 5[/tex]. Substitute in these values to find the point-slope equation of this line:
[tex](y - y_{0}) = m\, (x - x_{0})[/tex].
[tex](y - 5) = 3\, (x - 2)[/tex].
Rewrite this point-slope equation in the requested format:
[tex]y - 5 = 3\, x - 6[/tex].
[tex]3\, x - 6 = y - 5[/tex].
[tex]3\, x = y + 1[/tex].
[tex]3\, x - y = 1[/tex].
[tex]3\, x + (-1)\, y = 1[/tex].