Question

5. The sequence of numbers below is missing the
fourth value. Which of the following is the form
of the missing value in its lowest terms?
3/11, 6/16,9/21,__, 15/31, 18/36
a. 12/25
b. 4/13
c 6/13
d. 1/2
E.7/26

Answer 1

Answer:

C

6/13

Step-by-step explanation:

Comment

This is not a true sequence. It just has the same things done to the numerator as to the denominator.

The numerator (top part of the fraction).

Add 3 to the previous numerator's top

So 3 + 3 = 6 which is the numerator of the second term.

15 + 3 = 18 which is the numerator of the seventh term.

So the numerator of the 4th term is 9 + 3 = 12

The Denominator

The difference there is 5

So 21 + 5   = 26

The answer is

12/26

This reduces down to 6/13