Question

Determine the solutions of the equation:


Absolute value of the quantity one third times x plus 9 end quantity minus 3 equals 21.


x = −11 and x = 5

x = −81 and x = 45

x = −99 and x = 45. <<<< THIS IS IT

x = −99 and x = 99




PLEASE HELP!!!

Answer 1

The solutions to the absolute value equation given by the word phrase; Absolute value of the quantity one third times x plus 9 end quantity minus 3 equals 21 are; x = −99 and x = 45.

What are the solutions of the absolute value equation as given in the task content?

It follows from the task content that the solutions to the absolute value equations as given by the word phrase are to be determined.

Given;

| (1/3)x + 9 | - 3 = 21

Add 3 to both sides;

| (1/3)x + 9 | = 24

Hence, the result equations are; (1/3)x + 9 = 24 OR (1/3)x + 9 = -24.

Therefore, we have;

(1/3)x + 9 = 24

(1/3)x = 24 - 9

(1/3)x = 15

x = 45.

Also, considering the other equation;

(1/3)x + 9 = -24

Subtract 3 from both sides;

(1/3)x = -33

Multiply both sides by 3;

x = -99.

Ultimately, the solutions of the equation are;

x = −99 and x = 45.

Therefore, the solutions to the absolute value equation given by the word phrase; Absolute value of the quantity one third times x plus 9 end quantity minus 3 equals 21 are; x = −99 and x = 45.

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