Question

A truck driver is driving from Nome, Alaska, to Death Valley, California. Because he is traveling between locations with extreme temperatures, he needs to check the weather continuously to make sure the gas in his truck remains in liquid form. The gas he uses freezes at −40° F and evaporates at 140° F.

Part A: Write an inequality to represent the temperatures at which the gas in the truck will remain in liquid form.

Part B: Describe the graph of the inequality completely from Part A. Use terms such as open/closed circles and shading directions. Explain what the solutions to the inequality represent.

Part C: In January 1989, the temperature in Nome, Alaska, dropped to −49° F. Would the gas in the driver's truck have remained in liquid form so he could have driven on this day? Why or why not?

Answer 1

Answer:

Step-by-step explanation:

part c is the correct i beleive

Answer 2

Answer:

A)  -40 < x < 140

B)  See below

C)  No

Step-by-step explanation:

Part A

Define the variable:

• Let x be the temperature of the gas in degrees Fahrenheit .

Given information:

The gas freezes at −40° F and evaporates at 140° F.

Therefore, an inequality to represent the temperatures at which the gas in the truck will remain in liquid form is:

$\boxed{-40 < x < 140}$

Part B

When graphing inequalities:

• < or > : open circle
• ≤ or ≥ : closed circle
• < or ≤ : shading to the left
• > or ≥ : shading to the right

Therefore, the graph of the inequality from Part A is:

• Open circle at x = -40.
• Open circle at x = 140.
• Shading to the right of x = -40 and to the left of x = 140.

(See attachment).

The solutions to the inequality are represented by the shaded region.

Part C

If the temperature was −49° F, the gas in the driver's truck would not have remained in liquid form as -49 < -40 and so −49° F is outside the range of solutions of the inequality.  Therefore, the driver would not have been able to drive on this day.