In Exercises 19-24, solve the equation. Determine
whether the equation has one solution, no solution, or
infinitely many solutions. (See Example 3.)
19. 3t+ 4 = 12 + 3t
20. 6d+ 8 = 14 + 3d
21. 2(h+ 1) = 5h - 7
22. 12y + 6 = 6(2y + 1)
23. 3(4g + 6) = 2(6g + 9)
24.
5(1+2m)=(8 + 20m)

In Exercises 1924 solve the equation Determine whether the equation has one solution no solution or infinitely many solutions See Example 3 19 3t 4 12 3t 20 6d class=

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Step-by-step explanation:

Given is a linear equation in t

If we want to simplify we find that 3t gets cancelled and we get

This is an impossible situation.

This implies that original equation has no solution at all

Hence answer is

the given has no solution

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