Question

Carbon14 has half life of 5,730 years. If an archaeological sample has only one-fourth of the radioactivity of a similar sample from today how old is the archaeological sample

Answer 1

Given

The half-life of C-14 = 5730 years.

The half- life time is the time taken by the object to attain its position till the half of its initial value.

i.e after 5730 years only half of the C-14 carbon will exists.

To retain one-fourth of the sample, another cycle of 5730 years is required.

This means 2 half-lives should have passed to retain one-fourth of the sample.

so to calculate it's age

$\frac{t}{\frac{t}{\frac{1}{2} } }$ = 2

where t = the age of the sample

with t(1/2) = the half-life time of the sample = 5470 years

2 = the number of half- lives passed

therefore

$\frac{t}{5730}$ = 2

t = 2*5730 = 11460 years

When only one-fourth of the sample will remain, the age of the sample will be 11460 years

To know more about half-life,

https://brainly.com/question/12746367

#SPJ1