Question

A student is running an experiment in which 65.0 grams of BaI2 is needed, but the only jar of reagent in the lab is labelled barium iodide dihydrate. How many grams of the hydrate must the student weigh out in order to get the desired amount of the anhydrous compound?

Answer 1

We would require 71g of the dihydrate.

What is the mass of the dihydrate?

We know that a compound could have a water of crystallization. This water of crystallization is attached to the molecule of the compound and is involved when we are calculating the molar mass of the compound.

Now we have the mass  of the anhydrous compound that is required as 65 g.

Molar mass of the anhydrous compound = 391 g/mol

Molar mass of the dihydrate 427 g/mol

Given that;

Number of moles of hydrated compound = Number of moles of anhydrous compound

x/427 = 65/391

x = 65/391 * 427

x = 71 g

Thus, we would require 71g of the dihydrate.

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