Question

A bag contains 3 red
marbles, 5 blue marbles and 4 green marbles. If three marbles
are drawn out of the bag, what is the exact probability that all three marbles drawn
will be blue?

Can y’all help me please??

Answer 1

total items = 5 + 4 +3

= 12

Given item = 4

p = 3/12

=1/4

Answer 2

Answer:

$\frac{5}{42}$

Step-by-step explanation:

It makes a difference if the marbles are place bag into the bag after selecting.  Since this is not stated, I am assuming that once a marble is selected, it is not placed back in the bag.

$\frac{5}{9}$ x $\frac{4}{8}$ x $\frac{3}{7}$ = $\frac{60}{504}$  This simplified would be $\frac{5}{42}$  The 5 represent the number of blue marbles available our of 9 total marbles.  Next, we only have 4 blue marbles available out of a total of now 8 marbles and lastly, for the third draw we only have 3 blue marbles available and only 7 total marbles are left.

If the marbles are replaces that changes the problem and the answer would be $\frac{5}{9}$ x $\frac{5}{9}$ x $\frac{5}{9}$ = $\frac{121}{729}$