Question

Find an equation of the line perpendicular to 3y=x+3 that passes through the point (5,8). Write the answer in slope-intercept form, y=mx+b, with all fractions written in the lowest terms.

Answer 1

Let the equation of the line perpendicular to line 3x+2y=16 is:-

2x - 3y = C. ………………(1)

Line (1) passes through the point (9,-2), therefore

2×9 - 3×(-2)= C

or, C = 24.

Thus, the required equation is:-

2x - 3y = 24.

or, 3y = 2y - 24.

or, y = (2/3).x + (-8). Answer.