Question

find three consecutive integers such that the sum of the first and twice the second is 98 minus three times the third

Answer 1

${ \qquad\qquad\huge\underline{{\sf Answer}}}$

Let the numbers be : x, x + 1 and x + 2 ~

now, according to given condition :

$\qquad \sf  \dashrightarrow \: x + 2(x + 1) = 98 - 3(x + 2)$

$\qquad \sf  \dashrightarrow \: x + 2x + 2 = 98 - 3x - 6$

$\qquad \sf  \dashrightarrow \: x + 2x + 3x = 98 - 6 - 2$

$\qquad \sf  \dashrightarrow \: 6x = 90$

$\qquad \sf  \dashrightarrow \: x = 90 \div 6$

$\qquad \sf  \dashrightarrow \: x = 15$

So, tge required numbers are : 15, 16 and 17