Question

A ball is rolled at a velocity of 2.0 m/s. After 3.6 seconds, it comes to a stop. What is the
acceleration of the ball?

Answer 1

Answer: Given -

• Initial velocity of the ball, u = 0 m/s
• final velocity of the ball, v = 12 m/s
• Time taken = 36 sec

To find -

• Acceleration of the ball.

Solution -

$A=\frac{v-u}{t}\\A=\frac{12-0}{36} \\A=\frac{12}{36} \\A=0.33m/s^2$

Therefore, the acceleration of the ball is 0.33 m/s².

I hope this helps.