Question

the figure, ray OJ is perpendicular to ray OE. If ∠JOL=6x+10 and ∠LOE=x+10, find the measure of ∠LOE.

Answer 1

Answer:

∠ LOE = 20°

Step-by-step explanation:

since OJ is perpendicular to OE then ∠ JOE = 90°

from the diagram

∠ JOL + ∠ LOE = ∠ JOE ( substitute values )

6x + 10 + x + 10 = 90

7x + 20 = 90 ( subtract 20 from both sides )

7x = 70 ( divide both sides by 7 )

x = 10

Then

∠ JOE = x + 10 = 10 + 10 = 20°