the figure, ray OJ is perpendicular to ray OE. If ∠JOL=6x+10 and ∠LOE=x+10, find the measure of ∠LOE.

Answer:
∠ LOE = 20°
Step-by-step explanation:
since OJ is perpendicular to OE then ∠ JOE = 90°
from the diagram
∠ JOL + ∠ LOE = ∠ JOE ( substitute values )
6x + 10 + x + 10 = 90
7x + 20 = 90 ( subtract 20 from both sides )
7x = 70 ( divide both sides by 7 )
x = 10
Then
∠ JOE = x + 10 = 10 + 10 = 20°