The speed over the ground is 0 m / s .
As it is given that mosquito is flying at 2 m / s relative to the air caught in a 2 m / s right angle crosswind.
As we know that speed over the ground is the difference between the flight speed and resistance speed .
So , the general equation for the speed over the ground is :
v = Flight Speed - Resistance Speed
This implies , v = 2 m / s - 2 m / s
v = 0 m / s
Hence , the speed over the ground is 0 m / s .
To learn more about relative speed / Relative Velocity kindly check :
https://brainly.com/question/17228388
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