Question

Calculate with full procedure:
a. The number of Fe atoms in 363.2 kg of iron.
R= 3.916 x 1027 Fe atoms

b. The mass of a sample of 1.0 x 1012 atoms of metallic silver.
R= 1.8 x 10-10g Ag

c. The number of Argon atoms in a 5.25 mg Ar sample.
R=7.91 x 1019 atoms

d. The mass of a sample of aluminum that contains the same number of atoms as 35.55 g of zinc.
R= 14.66g Al

Answer 1

Answer:

5.3x1022 atoms

Explanation:

If we were to represent five grams of iron in term of the number of atoms of iron, we would get 5.3x1022 atoms of iron.