Answer:
Option B
Step-by-step explanation:
In the figure, attached, given line passes through two points ( 3, 1 ) and ( 0, 1 ).
So slope of the line will be = [tex]\frac{(y-y')}{(x-x')}[/tex]
= [tex]\frac{(1+1)}{(3-0)}[/tex]
= [tex]\frac{2}{3}[/tex]
Now a line which is parallel to this line will have same slope as ( [tex]\frac{2}{3}[/tex] ) and equation will be y = [tex]\frac{2}{3}[/tex]x + c
Now it is given that this line passes through ( -3, 0 )
[ x-intercept given as (-3)]
We plug in the values in the equation to get the value of c
0 = [tex]\frac{2}{3}[/tex] ( -3) + 6
0 = -2 + c ⇒ c = 2
Therefore, equation will be y = [tex]\frac{2}{3}[/tex]x + 2
Option B is the answer.
