Question

What is the frequency of radiation emitted by a photon of light if the energy released during its transition to ground state is 3.611 × 10-15 joules?
(Planck's constant is 6.626 × 10-34 joule seconds)

Answer 1

E=hf
3.611x10⁻¹⁵ = (6.63x10⁻³⁴)(f)
f= $\frac{3.611x10 x^{-15} }{6.63x10 x^{-34} }$
f=5.45x10¹⁸