Question

what is the value of b^2-4ac for the following equation 10x^2-19x+6=0

Answer 1

b^2 - 4ac

10x^2 - 19x + 6 = 0

This is for the quadratic formula

Your a value is the scalar of the x^2  (10)
Your b value is the scalar of the x   (-19)
Your c value is the constant   (6)