Question

Solve the inequality and express your answer in interval notation.
x^2 + 12x +7 < 0

Answer 1

Solution:

B. $(-6-\sqrt{29},-6+\sqrt{29})$

Hope this helps! If so, lmk! Thanks and good luck!

Answer 2

Answer: (-6-$\sqrt{29}$, -6+$\sqrt{29}$) ==> D

Step-by-step explanation:

x^2 + 12x +7 < 0

x^2+12x+36-29<0

(x+6)^2-29<0

(x+6)^2<29

x+6<$\sqrt{29}$

x<-6+$\sqrt{29}$

x+6>-$\sqrt{29}$

x>-6-$\sqrt{29}$

(-6-$\sqrt{29}$, -6+$\sqrt{29}$) ==> D

-6-$\sqrt{29}$ and -6+$\sqrt{29}$ aren't included in the solution since if these values are plugged in to x^2 + 12x +7, the expression will equal 0. That's not supposed to happen. The expression is supposed to be LESS than 0.