Question

a 6.96 nc charge is located 1.82 m from a 4.02 nc point charge. (a) find the magnitude of the electrostatic force that one charge exerts on the other. n (b) is the force attractive or repulsive? attractive repulsive

Answer 1

The electric force is 7.60 x 10¯⁸ N.

We need to know about the electrostatic force to solve this problem. The electrostatic force produced by charges interacting each other, whose strength is given by the equation

F = k.Q1 . Q2/r²

where F is the electrostatic force, Q1 and Q2 is the charge and r is the radius.

From the question above, we know that

k = 9 x 10⁹ Nm²/C²

Q1 =e = 6.96 x 10¯⁹ C

Q2 = e = 4.02 x 10¯⁹ C

r = 1.82 m

The electrostatic force will attract each other when the charges are different and will repel each other when the charges are same.

F = k.Q1 . Q2/r²

F = 9 x 10⁹ . 6.96 x 10¯⁹ . 4.02 x 10¯⁹/1.82²

F = 7.60 x 10¯⁸ N

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