Question

a horizontal clothesline is tied between 2 poles, 10 meters apart. when a mass of 1 kilograms is tied to the middle of the clothesline, it sags a distance of 1 meters. what is the magnitude of the tension on the ends of the clothesline?

Answer 1

By analyzing the vector, the clothesline tension is 25 N.

We need to know about vectors to solve this problem. Force is included in vectors that have magnitude and direction. It can be written as

F = (Fx i + Fy j) N

where F is the force vector, Fx is the x-axis component and Fy is the y-axis component.

From the question we know that :

x = 10 m

(midpoint = 5m)

y = 1 m

m = 1 kg

Find the weight

W = m . g

W = 1 x 10

W = 10N

There are two y-axis components of the tension that hold the clothes. Because of static conditions, we can write

∑Fy = 0

Ty + Ty - W = 0

2Ty - 10 = 0

2Tsinθ - 10 = 0

Find sinθ

sinθ = y/x

sinθ = 1/5

Substitute the sinθ

2Tsinθ - 10 = 0

2T(1/5) - 10 = 0

2T/5 = 10

T = 25 N

Hence, the clothesline tension is 25 N.

For more about vectors at: https://brainly.com/question/25811261

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