Based on the calculation below, the number of families that has to be surveyed is 2,654.
From the question, we have:
SD = population standard deviation = $1200
Confidence level = 99%
A = Average or half length of the interval = $60
Also, we have:
z-multiple at 99% confidence level = 2.576
The sample size or the number of families that has to be surveyed can be calculated using the following formula:
Number of families to survey or sample size =
Number of families to survey or sample size = ((z-multiple * SD) / A)^2 ....................... (1)
Substituting all the values into equation (1), we have:
Number of families to survey or sample size = ((2.576 * 1200) / 60)^2 = 51.52^2 = 2,654.3104 = 2,654
Learn about the sample size here: https://brainly.com/question/24158610.
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