Question

A chemist recorded the change in temperature of a cooling liquid as −25.5°F over a 1.5 minute period. The temperature fell at a constant rate.

What was the rate of change in temperature

Answer 1

The rate of change in temperature is −17°F/min

Rate of change of a function

The formula for calculating the rate of change of a function is expressed as:

Rate of change = rise/run

This is also known as the slope of the function

Given the following parameters

Temperature = −25.5°F

Cooling time = 1.5mins

Determine the rate of change

Rate = −25.5°F/1.5min

Rate = −17°F/min

Hence the rate of change in temperature is −17°F/min

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