the rate of increase of surface area of the balloon is a) 16π b) 24π c) 48π
I found the complete question on Study.com, which is
A spherical balloon is being inflated. Find the rate of increase (with respect to the radius r) of the surface area (S=4πr2) when:
a) r=2 inches
b) r=3 inches
c) r=6 inches
Area of a spherical balloon is S = 4πr2. So the increasing rate of area of the balloon with respect to the radius r is
dS/dr = 8πr
Therefore, the rate of increase of the surface area
a) 16π
b) 24π
c) 48π
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