Question

A particle moving uniformly along the x axis is located at 15.7 m at 1.46 s and at 3.33 m at 3.57 s. find its displacement during this time interval.

Answer 1

The displacement of the particle is 12.37 m in negative x- direction.

In this question,

Displacement is the distance moved in a straight line, in a given direction, from the starting point. It is a vector quantity and has a direction and magnitude. It is represented as an arrow that points from the starting position to the final position.

Thus, Displacement = Final position - Initial position

Here,

Initial position = 15.7 m

Final position = 3.33 m

Now, Displacement = 3.33 - 15.7

⇒  Displacement = -12.37 m

Thus, the displacement of the particle is 12.37 m in negative x- direction.

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