The answer to the given question is A.)12 and B.)10
relation f from a set A to a set B is said to be a function if every element of set A has one and only one
image in set B.
In other words, no two distinct elements of B have the same preimage.
The given function is
a. F(x) = 2x^2 + 4x – 5
We have to find f(-4) + f(1) which means x = -4 and x = 1
Substituting the values
f(-4) = 2 (-4)2 + 4 (-4) -5
f(-4) = 32 – 16 – 5
f(-4) = 11
Similarly solving for f(1)
F(1) = 2 (1)2 + 4 (1) -5
f(1) = 1
therefore, f(-4) + f(1) = 11 + 1
= 12
b. f(-4) – f(1)
we have f(-4) = 11 and f(1) = 1
therefore, f(-4) – f(1) = 11 – 1
= 10
Therefore, the values of the given parts of the question are 12 and 10
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