Question

two dogs run around a circular track 300 feet long. one dog runs at a steady rate of 15 feet per second, the other at a steadt rate of 12 feet per second. suppose they start at the same point and time. what is the least number of seconds that will elapse before they are again together at the starting point?

Answer 1

The least number of seconds that will elapse before they are again together at the starting point is 100 seconds.

How do we calculate the least number of time taken?

Number of seconds it takes Dog 1 to circle the track once = Length of the circular track / Dog 1 feet per second = 300 / 15 = 20

Number of seconds it takes Dog 2 to circle the track once = Length of the circular track / Dog 2 feet per second = 300 / 12 = 25

From the above, we have:

Dog 1's prime factor = 20 = 2 * 2 * 5

Dog 2's prime factor = 25 = 5 * 5

The Least Common Multiple (LCM) of 20 and 25 from the above is as follows:

LCM = 2 * 2 * 5 * 5 = 100 seconds

This implies that the two dogs will again be together at the starting point in 100 seconds.

Learn more about Least Common Multiple (LCM) here: https://brainly.com/question/17256135.

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