Question

9^x=27^(x+2)
how do I do that? I don't get how to do it with different bases

Answer 1

$9^x=27^{x+2}\\ 3^{2x}=3^{3(x+2)}\\ 2x=3(x+2)\\ 2x=3x+6\\ 3x-2x=-6\\ x=-6$