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cube made of a conducting material of side length 10 cm is reshaped to be a wire of
electric resistance 20 92, if the resistivity of the material of the cube is 1 × 10-7 0.m.
Calculate the length of the wire and its radius. (I = 3.14)

Respuesta :

The length of the wire is 447.2m and its radius is 8.43 * 10^(-4)m.

side length of cube (l) = 10cm = 0.1m

  • A substance can impede the flow of electricity through it because of a physical feature called resistance. Resistance is influenced by a material's physical properties, chemical makeup, and temperature.
  • resistance of wire (R) = 20Ω
  • A material's electrical resistivity, which gauges how effectively it resists electric current, is one of its essential properties. A substance that readily permits electric current has low resistance.
  • resistivity of wire (ρ) = 10^(-7)Ωm
  • Suppose the volume of the cube is V, the volume of the wire is V' ", the length of the wire is L, the area of cross-section of the wire is A, and the radius of the wire is r.
  • volume of cube = volume of wire
  • V = V'
  • l^3 = A*L
  • (0.1)^3 = A*L
  • A*L = 10^(-3)            -equation(1)
  • For wire,
  • R = ρ*L/A
  • 20 = 10^(-7) L/A
  • A = 10^(-7) L/20       -equation(2)
  • Using equations (1) and (2):
  • (10^(-7) L/20)*L = 10^(-3)
  • Upon solving, we get L = 200√5m = 447.2m
  • Substituting this value of L in equation (1),
  • A * 447.2 = 10^(-3)
  • πr² * 447.2 = 10^(-3)
  • Upon solving, we get r = 8.43 * 10^(-4)m

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